As name suggested, the antiderivative of a function f is a function F such that derivative of F will give f i.e, F'(x) = f(x) The identified function F is known as prime antiderivative of f. It is well-known that the derivative of a constant c is zero. Thus, the general antiderivative of f is F+ c.

The antiderivative is also known as ** Indefinite Integration of f **. The indefinite integration is denoted as
\[\int f(x) dx = F(x) + c.\]

#### How to find the antiderivative of a function f?

Example: Find the antiderivative of f(x) = x^2 .

To find the antiderivative of a given function, we have to search a function whose derivative is the given function. Here is the steps:

- Step 1 : The function whose derivative will contain x^2 is x^3
- Step 2 : But derivative of x^3 will give 3 x^2
- Step 3: Thus, the function whose derivative will be exactly x^2 is \frac{x^3}{3}.
- Step 4 : Finally, the antiderivative of f(x) = x^2 is F(x) = \frac{x^3}{3} + c .

Example: Find the antiderivative of f(x) = \sin(x).

Here is the thought process:

- Step 1 : The function whose derivative will contain \sin(x) is \cos(x)
- Step 2: But derivative of \cos(x) will give -\sin(x)
- Step 3: Thus, the function whose derivative will be exactly \sin(x) is \(- \cos(x) \)
- Step 4 : Finally, the antiderivative of f(x) = \sin(x) is F(x) = - \cos(x) + c .

Example: Find the antiderivative of f(x) = e^{2x}.

Here is the thought process:

- Step 1 : The function whose derivative will contain e^{2x} is \( e^{2x} \)
- Step 2: But derivative of e^{2x} will give 2e^{2x}
- Step 3: Thus, the function whose derivative will be exactly e^{2x} is \(\frac{e^{2x}}{2} \)
- Step 4 : Finally, the antiderivative of \(f(x) = e^{2x}\) is \(F(x) = \frac{e^{2x}}{2} + c. \)

Function \(f(x)\) | Antiderivative \(F(x)\) |

\(f(x) = x^m\) | \(F(x)= \frac{x^{m+1}}{m+1}+c, \; m \neq – 1 \) |

\(f(x) = e^{m x}\) | \(F(x)= \frac{e^{m x}}{m}+c\) |

\(f(x) = \sin(m x)\) | \(F(x)= – \frac{\cos(m x)}{m}+c\) |

\(f(x) = \cos(m x)\) | \(F(x)= \frac{\sin(m x)}{m}+c\) |

\(f(x) = \sec^2(m x)\) | \(F(x)= \frac{\tan(m x)}{m}+c\) |

\(f(x) = \tan(mx)\sec(m x)\) | \(F(x)= \frac{\sec(m x)}{m}+c\) |

\(f(x) = \csc^2(m x)\) | \(F(x)= -\frac{\cot(m x)}{m}+c\) |

\(f(x) = \cot(mx)\csc(m x)\) | \(F(x)= – \frac{\csc(m x)}{m}+c\) |

\(f(x) = \frac{1}{x}\) | \(F(x)= \ln\left(|x|\right) +c\) |

\(f(x) = \frac{1}{1+x^2}\) | \(F(x)= \tan^{-1}(x) +c\) |

\(f(x) = \frac{1}{\sqrt{1-x^2}}\) | \(F(x)= \sin^{-1}(x) +c\) |

\(f(x) = a^x\) | \(F(x)= \frac{a^x}{ln(a)} +c\) |

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The Antiderivatives are required to solve the integration in next section and calculus 2